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Distinguish repr(C) ZSTs from others in ABI compatibility rules
#157973
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| Original file line number | Diff line number | Diff line change | ||||
|---|---|---|---|---|---|---|
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@@ -1841,7 +1841,15 @@ mod prim_ref {} | |||||
| /// call will be valid ABI-wise. The callee receives the result of transmuting the function pointer | ||||||
| /// from `fn()` to `fn(i32)`; that transmutation is itself a well-defined operation, it's just | ||||||
| /// almost certainly UB to later call that function pointer.) | ||||||
| /// - Any two types with size 0 and alignment 1 are ABI-compatible. | ||||||
| /// - Any two types fulfilling all the following conditions are ABI-compatible; | ||||||
| /// such types are said to have "trivial ABI": | ||||||
| /// - Size 0 | ||||||
| /// - Alignment 1 | ||||||
| /// - Not `repr(C)` | ||||||
| /// - Not a `repr(transparent)` wrapper around a type that fails to satisfy these conditions | ||||||
| /// - Not an array whose element type fails to satisfy these conditions | ||||||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. We exempt arrays for 2 reasons:
We could also simplify this clause by saying merely:
Suggested change
The downside would be a larger breaking change. Note that |
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| /// - A `repr(transparent)` type is ABI-compatible with its unique field that does not have trivial ABI | ||||||
| /// (as defined above). If there is no such field, the type has trivial ABI. | ||||||
| /// - A `repr(transparent)` type `T` is ABI-compatible with its unique non-trivial field, i.e., the | ||||||
| /// unique field that doesn't have size 0 and alignment 1 (if there is such a field). | ||||||
| /// - `i32` is ABI-compatible with `NonZero<i32>`, and similar for all other integer types. | ||||||
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I think the implication here is that
()is repr(C)? Am I reading that right? Where do we make that guarantee? Or is the thinking that the language here would make()and#[repr(C)] struct Foo;not ABI compatible?One callout is that ZSTs aren't (I think?) standardized -- C and C++ without extensions both require types to be non-ZST if I remember right (e.g., see https://stackoverflow.com/a/2632075). Maybe that has changed since then though?
It seems like at minimum, it would be nice to avoid weakening this guarantee for Rust ABI even if we do so for C ABIs as a result of the weird platforms.
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Yes, this.