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/*
1768. Merge Strings Alternately
You are given two strings word1 and word2. Merge the strings by adding letters in alternating order, starting with word1. If a string is longer than the other, append the additional letters onto the end of the merged string.
Return the merged string.
Example 1:
Input: word1 = "abc", word2 = "pqr"
Output: "apbqcr"
Explanation: The merged string will be merged as so:
word1: a b c
word2: p q r
merged: a p b q c r
Example 2:
Input: word1 = "ab", word2 = "pqrs"
Output: "apbqrs"
Explanation: Notice that as word2 is longer, "rs" is appended to the end.
word1: a b
word2: p q r s
merged: a p b q r s
Example 3:
Input: word1 = "abcd", word2 = "pq"
Output: "apbqcd"
Explanation: Notice that as word1 is longer, "cd" is appended to the end.
word1: a b c d
word2: p q
merged: a p b q c d
Constraints:
1 <= word1.length, word2.length <= 100
word1 and word2 consist of lowercase English letters.
*/
/*
==========Approach=============
=======Two Pointer============
*/
class Solution {
public:
// Time Complexity O(n+m)
// Space complexity O(1)
string mergeAlternately(string word1, string word2) {
string ans="";
int i =0,j=0;
while(i<word1.size() && j<word2.size()){
ans.push_back(word1[i++]);
ans.push_back(word2[j++]);
}
while(i<word1.size()){
ans.push_back(word1[i++]);
}
while(j<word2.size()){
ans.push_back(word2[j++]);
}
return ans;
}
};