Replies: 3 comments 4 replies
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I probably do not understand the question. The "boundary elements" do not exist in the grid you generate in your example code. You can get full connectivity information from e.g. the ExclusiveTopology, or you just reconstruct the information you need manually. |
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Might be useful if you explain a bit more what you want to achieve in case there is a better solution (since this sounds a little bit like an XY problem). |
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Thanks. The aim is to convert mesh in Comodo.jl https://github.com/COMODO-research/Comodo.jl to Ferrite for the finite element The Comodo mesh for a simple case is: No I want to convert this mesh to Ferrite grid, first I get grid.cells and grid.nodes Now How to Create The I generate the grid: The main question here is that in I hope now it is more clearer |
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Dear Ferrite Developers,
How can we find the element connectivity of the boundary surface and its corresponding global cell id in the grid, assuming that we don't have facetsets, we need Ferrite.FacetIndex(element_id, local_face_id)
for example in the following code
Thank you so much in advance
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